Surface | Average Energy Flux |
---|---|
Solar electromagnetic radiation | 241.5 W m-2 |
Energetic particles (sun and space) | 0.001 W m-2 |
Geothermal | 0.06 W m-2 |
Anthropogenic (fossil fuels, nuclear energy) | 0.02 W m-2 |
The position of the Sun in the sky and the path of the solar beam.
Processes of absorption, reflection and scattering of radiation through the atmosphere determine the available short-wave radiation reaching Earth’s surface.
Surface | Average Energy Flux |
---|---|
Solar electromagnetic radiation | 241.5 W m-2 |
Energetic particles (sun and space) | 0.001 W m-2 |
Geothermal | 0.06 W m-2 |
Anthropogenic (fossil fuels, nuclear energy) | 0.02 W m-2 |
\[ e = hv \qquad(1)\]
\[ E = \frac{2*h*c}{\lambda^{5}}*\frac{1}{e^{\frac{h*c}{\lambda*\sigma_b*T}}-1} \qquad(2)\]
\[ E_b = \sigma_b T^4 \qquad(3)\]
where \(\sigma = 5.67 * 10^-8\)
\[ \lambda_{max} = \frac{b}{T} \qquad(4)\]
\[ \zeta_{\lambda} = \epsilon_{\lambda} \qquad(5)\]
Solar declination (\(\delta\)): Angle between Sun’s rays and equatorial plane.
Latitude (\(\Phi\)): Angle between the equatorial plane and the site of interest (point P in the figure).
Hour angle (h): Angle through which the Earth must turn to bring the meridian of the site P directly under the Sun. It is a function of the time of day.
\(\delta\) only depends upon day of year, which gives returns \(\delta\) in radians
\[ \begin{eqnarray} \delta = & 0.006918 - 0.399912 \cos( \gamma)+0.070257 \sin( \gamma) \\ & -0.006758 \cos(2 \gamma) + 0.000907\sin(2\gamma) \nonumber \\ & -0.002697\cos(3\gamma)+0.00148 \sin(3\gamma) \nonumber \end{eqnarray} \qquad(6)\]
where \(\gamma\) is the fractional year and DOY is the day of the year:
\[ \gamma = \frac{2 \pi }{365} (DOY-1) \qquad(7)\]
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
def Solar_Declination(DOY):
gamma = 2*np.pi/365*(DOY-1)
delta = 0.006918 - 0.399912 * np.cos(gamma)+0.070257 *np.sin(gamma)-0.006758 *np.cos(2*gamma) + 0.000907*np.sin(2*gamma)-0.002697*np.cos(3*gamma)+0.00148 *np.sin(3*gamma)
return(delta*180/np.pi)
Dates = pd.date_range('2024-01-01','2024-12-31')
Declination = Solar_Declination(Dates.dayofyear)
plt.figure(figsize=(6,3))
plt.plot(Dates,Declination)
plt.ylabel('Solar Declination')
What is the solar declination on June 21st?
Solar Zenith (Z) Angle between Sun’s rays and observer’s local zenith.
Azimuth angle (\(\Omega\)) Angle between projections onto local horizontal for both Sun rays and true North (0=360°).
Solar Altitude (\(\beta\)) Angle between Sun’s rays and observer’s local horizon (\(\beta\) = 90°- Z)
\[ \cos(Z) = \sin(\beta) = \sin(\Phi)\sin(\delta)+\cos(\Phi)\cos(\delta)\cos(h) \qquad(8)\]
where the hour angle (h) is a function of local apparent time (LAT):
\[ h = 15^{\circ}(12-LAT) \qquad(9)\]
Add (subtract) 4 min to LST for each degree of longitude east (west) of the standard meridian of the time zone.
\[ LMST = (TZ) + (\lambda-TZ_{m})\frac{4}{60} \qquad(10)\]
where \(\lambda\) is longitude, \(TZ\) is time in LST (e.g., PST = UTC-8) in hours, and \(TZ_{m}\) is the central meridian for a given time zone (e.g., PST = -120 \(^{\circ}\)). You can then calculate the local apparent time LAT as:
\[ LAT = LMST-\Delta LAT \qquad(11)\]
and \(\Delta LAT\) is: \[ \begin{eqnarray} \Delta LAT = & 229.18[0.000075+0.001868\cos(\gamma)-0.032077\sin(\gamma) \\ & -0.014615\cos(2\gamma)-0.040849\sin(2\gamma)] \end{eqnarray} \qquad(12)\]
Kepler’s first law: states that planets follow an elliptical orbit, with the Sun in one focus. This implies that the Earth-Sun distance is changing during a year.
Kepler’s second law: a planet moves fastest when it is near the perihelion and slowest when it is near Aphelion.
Timezone not provided, estimating for -127.5, 50
(0.0, 366.0)
\(R_p\) the radiative flux density on a surface perpendicular to the beam and Z is the zenith angle of incidence (i.e the angle between the surface and the direction of the beam).
\[ R_s = R_p cos(Z) \qquad(13)\]
The radiant flux density (irradiance) at the top of the atmosphere normal to the solar beam an at Earth’s mean distance from Sun.
\(R_av\) is the mean distance Earth-Sun over the year and \(R\) is the actual distance Earth-Sun at a given time.
The solar input at top of the atmosphere at any time and location hence is given as \(I_ex\): \[ I_{ex}=I_0(\frac{R_{av}}{R})^2\cos(Z) \qquad(14)\]
where \(I_0 \approx 1361 W m^{-2}\), \(\cos(Z)\) applies the cosine law of illumination, and \((\frac{R_{av}}{R})\) adjusts the solar constant Earth’s elliptic orbit:
\[
\begin{eqnarray}
(\frac{R_{av}}{R})^2 = & 1.00011+0.034221\cos(\gamma)+0.001280\sin(\gamma)+\\
&0.000819\cos(2\gamma)+0.000077\sin(2\gamma)
\end{eqnarray}
\qquad(15)\]