This type of turbulence is likely to occur on a calm sunny day with minimal winds:
The integral length scale \(l\) of a turbulent flow depends on the processes that create it; \(l\) is a measure of the largest eddy size in the flow.
For mechanical turbulence this is the size of the obstacle, but
Limit 1: height above ground
Limit 2: depth of the PBL
The Kolmogorov microscale (\(\eta\)) depends on the fluid’s viscosity \(\upsilon\), and the rate of energy dissipation to heat (\(\epsilon\)):
\[ \eta = \upsilon^{\small\frac{3}{4}}\epsilon^{\small\frac{-1}{4}} \]{eq-Kolmogorov-Microscale}
In steady-state turbulence as often encountered in the ABL, the rate at which the energy is dissipated is exactly equal to the rate at which energy is supplied (by thermal and mechanical convection).
Scales of a turbulent flow are given by calculating a velocity spectrum:
Size of eddies can be viewed as wavelength (\(\lambda\)) or as frequency (\(v\)).
For a review of stability, see here
Thermal convection will always continue once induced under which type of atmospheric conditions:
Turbulent fluctuations are:
Initial eddies, created at the length scale \(l\) are likely directional:
In a fine structured canopy we observe a direct bypass from large eddies to small eddies without intermediate eddy sizes in the cascade.
Your midterm is:
Part 1 Written answers (45%)
1 Problem Question: multi-part, involving calculations
Energy balance and heat conduction
2 Short answers questions
Part 2 Automated marking (55%)